(1c)Total Magnification = Magnification of Objective Lens × Magnification of Eyepiece Lens.
Total Magnification = 10
Magnification of Objective Lens = 2
Let “E” represent the magnification of the eyepiece lens.
10 = 2 × E
E = 10/2
E = 5.
Static friction is a type of friction that exists between two surfaces in contact with each other when they are not moving relative to each other.
Coefficient of static friction (μs) = Force of static friction/ Normal force
Force of static friction = 3N
Normal force = 5N
μs = 3N / 5N = 0.6
The velocity ratio of a machine is the ratio of the distance moved by the effort to the distance moved by the load. It is a measure of the effectiveness of a machine in transmitting force.
Velocity ratio = distance moved by effort / distance moved by load
A second order lever has the load in the middle, with the effort applied on one side and the fulcrum on the other. The effort arm is longer than the load arm, which means the machine has a mechanical advantage. Examples of second order levers include wheelbarrows and nutcrackers WHILE A third order lever has the effort applied on one end, the load on the other end, and the fulcrum in between. The load arm is longer than the effort arm, which means the machine has a mechanical disadvantage. Examples of third order levers include tweezers and shovels.
– Angle of incidence (θ₁) = 60°
– Speed of light in air = 3×10⁸ m/s
– Speed of light in glass = 2×10⁸ m/s
The refractive index (n) of a medium can be calculated using the formula:
n = speed of light in vacuum / speed of light in the medium
Refractive index of air (n₁):
n₁ = speed of light in vacuum / speed of light in air
n₁ = 3×10⁸ m/s / 3×10⁸ m/s
n₁ = 1
Refractive index of glass (n₂):
n₂ = speed of light in vacuum / speed of light in glass
n₂ = 3×10⁸ m/s / 2×10⁸ m/s
n₂ = 1.5
Using Snell’s law to find the angle of refraction (θ₂):
n₁ × sin(θ₁) = n₂ × sin(θ₂)
1 × sin(60°) = 1.5 × sin(θ₂)
sin(θ₂) = (1 × sin(60°)) / 1.5
sin(θ₂) = sin(60°) / 1.5
θ₂ = arcsin(sin(60°) / 1.5)
θ₂ ≈ arcsin(0.86602540378 / 1.5)
θ₂ ≈ arcsin(0.57735026919)
θ₂ ≈ 35.26°
(i) Electric motors: Electromagnets are used in electric motors to convert electrical energy into mechanical energy. An electric motor contains an armature with a coil of wire that rotates within a magnetic field created by an electromagnet.
(ii) Magnetic resonance imaging (MRI): Electromagnets are used in MRI machines to create a strong magnetic field that aligns the protons in the body’s tissues. Radio waves are then used to create images of the body’s internal structures.
The soft iron bar can be converted to a magnet by placing it in contact with a bar magnet. When the bar magnet is brought close to the soft iron bar, the magnetic domains in the soft iron bar become aligned with the magnetic field of the bar magnet. This causes the soft iron bar to become magnetized and it will now be able to attract other magnetic materials.
Reactance refers to the opposition that an electrical circuit or component exhibits to the flow of alternating current (AC). It is a fundamental concept in understanding AC circuits and is closely related to the concept of impedance.
Xc = 1/(2πfC)
Xc = Capacitive reactance in ohms (Ω)
π = 3.14 (approximate value)
f = Frequency in Hertz (Hz)
C = Capacitance in Farads (F)
Capacitive reactance (Xc) = 3000Ω
Capacitance (C) = 5µF = 5 * 10-⁶F
π = 3.14
Rearranging the formula to solve for frequency (f):
f = 1/(2*π* Xc* C)
Substituting the given values:
f = 1/(2 * 3.14 * 3000 * 5 * 10-⁶ )
f = 1/(2 * 3.14 * 3000 * 0.000005)
f = 1/(6.28 * 0.015)
f = 1/0.0942
f=10.62Hz (approx. 2 decimal).
Photoelectrons are electrons that are emitted from a material when it absorbs electromagnetic radiation, typically in the form of photons (light). This phenomenon is known as the photoelectric effect.
Formula for threshold frequency;
F = E/h
E = Work function(Energy)
h= Plank’s constant (6.6×10-³⁴)
Converting the work function to joules:
Work function (ϕ) = 3.5 eV = 3.5 × 1.6 × 10-¹⁹ J = 5.6 × 10-¹⁹ J
Substituting the values
F = E/h
F= 5.6 × 10-¹⁹/6.6×10-³⁴
(i) Radiation exposure: X-rays are a type of ionizing radiation, which means that they can damage the DNA in cells and increase the risk of cancer. Exposure to high doses of X-rays can also cause radiation sickness, which can lead to nausea, vomiting, and hair loss.
(ii) Skin burns: X-rays can cause skin burns if the skin is exposed to a high dose of radiation. The severity of the burn depends on the dose of radiation and the duration of exposure.
(i) Soft X-rays have lower energy levels, while hard X-rays have higher energy level
(ii) Soft X-rays are commonly used in scientific research, such as studying atomic structures and electronic properties while Hard X-rays are more prevalent in medical and industrial applications, like diagnosing fractures, inspecting welds, or examining luggage at airports for security purposes.
(iii) Soft X-rays are more easily absorbed by matter than hard X-rays. As a result, softer X-rays are used to examine lighter elements, while harder X-rays are preferred for studying heavier elements in samples.
NECO Questions and Answers for Data processing; (OBJ, Theory) 2023
NECO Physics Questions and Answers For Practice
The questions below are the NECO 2022 Physics Practice Questions. Go through them and be ready to score high in your NECO 2022 Physics Examination.
1. The equation X
150 62 => Y 150 63 + -1 + energy, represents
A. Alpha decay
C. Gamma decay
D. Photon emission
ANSWER: B (Beta-decay)
2. The ice and steam points of a thermometer are 20mm and 100mm respectively. A temperature of 75 degree Celsius corresponds to Y mm on the thermometer. What is Y?
A. 100 mm
B. 70 mm
C. 80 mm
D. 60 mm
ANSWER: C (80mm)
3. When a yellow card is observed through a blue glass, the card would appear as
ANSWER: A (Black)
4. In a nuclear plant, the final mass of the products is 6.32×10^-27kg, while the initial mass of the reactant is 6.30×10^-27kg, the energy released in the process is (speed of light in vacuum 3.0×10^8m/s, 1eV = 1.6×10^-19J)
B. 11.25 MJ
ANSWER: A (11.25meV)
5. A 1.5kg stone was thrown vertically upward with an initial velocity of 42m/s, What is the potential energy of the stone at the highest point reached.
ANSWER: A (11.25meV)
6. When two objects P and Q are supplied with the same quantity of heat, the temperature change in p is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat of P to Q is
ANSWER: C (1:1)
7. The following statements were made by some students describing what happened during the determination of the melting point of solids
1. The temperature of the solid was constant until melting started
2. The temperature of the solid rose until melting started
3. During melting, the temperature was rising
4. During melting, the temperature was constant
5. The temperature continued to rise after all the solid had melted.
6. The temperature stopped rising after all the solid had melted. Which of the following gives correct statements in the right order?
A. 2, 4 and 5
B. 2, 3 and 6
C. 1, 3 and 6
D. 1, 3 and 5
ANSWER: A (2, 4, and 5)
8. A silver spoon and a wooden spoon are both at room temperature. The silver spoon is cooler to touch because silver
A. has a greater density
B. can be polished
C. is a less absorbent material than wood
D. is a better conductor of heat
ANSWER: D (is a better conductor of heat)
See: NECO Questions and Answers for Bookkeeping; (OBJ, Theory) 2023/2024
NECO Physics Essay Questions
1. (a) A student makes a model of an atom. The model contains 24 electrons, 25 protons and 26 neutrons. Some of these particles are inside a nucleus at the centre of the model.
(i) Determine the nucleon number (mass number) of the atom.
(ii) Explain why the model represents a charged atom.
(iii) The student makes a new model of a different isotope of the same element. Describe the nucleus of this new model.
Ans: 1 (a)
(i) 51 B1
(ii) more protons than electrons or different number of protons and electrons positive and negative do not cancel.
(iii) 25 protons. a different number of neutrons.
2. Fig. 1.1 shows the distance-time graph for two cyclists A and B. They start a 500 m race together but finish the race at different times.
(a) Use Fig. 1.1 to determine
(i) the distance between A and B at time t = 20s,
(ii) the difference in the time taken by A and B for the race.
(b) Cyclist C starts the race at the same time as A and B and covers the first 200m of the race at a constant speed of 5.0 m/s. He then accelerates and finishes the race at t = 60s.
(i) On Fig. 1.1, draw the distance-time graph for cyclist C.
(ii) Calculate the average speed of cyclist C for the whole race.
Ans: (a) (i) 60 m
(b) (i) straight line from origin to 200 m at 40s any line straight or curved from (40,200) to (60,500)
(ii) s = d/t or 500/60 = 8.3m/s
Neco Physics Objective Sample Questions;
If a satellite travels at a constant speed round the earth in a circular orbit,
1. Which of the quantities in the list below are scalars.
(a) acceleration (b) force (c) mass (e) speed.
2. The velocity of the satellite changes, but its speed is constant. State what is meant by velocity…………………….
3. Explain why the velocity changes……………………………
4. Explain what makes this satellite move in an orbit that is circular
Set a goal and work toward achieving it
I am confident that you have made the decision to succeed in NECO Physics 2023. Setting goals is the next thing you should do.
Not only have you promised yourself, “I will get an A in Neco Physics 2023,” but this isn’t all. You must establish a plan for how to implement it. To attain your goals, make a master strategy and timeframe.
Purchase the recommended physics textbook for the 2023 NECO exam.
NECO typically suggests literature for the test. You may use any reputable English Language textbook to study for the NECO 2023 exam, with the exception of NECO English Literature, where specific novels are required.
Some texts are more challenging to comprehend. Get a textbook that will clarify any things you are having trouble understanding so that your life will be better.
Do not Skip Physics Examples and Exercise you Will Come Across While Reading:
Many candidates are fond of skipping exercises and even examples while studying textbooks. In fact, we like notebooks so much that we could ask, “can I read my notebook and pass NECO Physics 2023?” Don’t be scared of attempting exercises in Biology. Face the challenges.
Note: The above questions are likely NECO Physics Questions and Answers, not the real questions
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, kindly drop your question in the comment box. NECO Physics Questions and Answers 2023